Timeline for Condition for set of the type $\{(a,b)|a \in A, \ b = f(a)\}$ to have empty interior if $A$ has empty interior [closed]
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| Sep 28, 2022 at 2:47 | history | closed |
Andreas Blass Stefan Waldmann Carl-Fredrik Nyberg Brodda user44191 Steven Landsburg |
Not suitable for this site | |
| Sep 10, 2022 at 15:05 | review | Close votes | |||
| Sep 28, 2022 at 2:47 | |||||
| Sep 10, 2022 at 10:02 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Aug 11, 2022 at 9:39 | answer | added | KP Hart | timeline score: 1 | |
| Aug 11, 2022 at 7:20 | review | Close votes | |||
| Aug 27, 2022 at 3:03 | |||||
| Aug 10, 2022 at 20:44 | comment | added | Riku | @Wojowu What do you mean? | |
| Aug 10, 2022 at 18:32 | comment | added | Wojowu | $X$ will have empty interior as a subset of $L^1\times L^1$, or $A\times L^1$ if you wish, for any subset $A$ and any function $f$. This is clear by contrapositive - if the interior was nonempty, then it would contain two different points $(a,b),(a,b')$. | |
| Aug 10, 2022 at 17:39 | history | asked | Riku | CC BY-SA 4.0 |