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Aug 8, 2022 at 2:42 comment added Marco Ripà I see... I posted this since usually we lose properties by climbing the ladder of hyperoperators, from multiplication (i.e., hyper-$2$) and above, but this is a very unique feature of hyper-4, that we cannot find in any higher-order operator, such as pentation. Now, my first thought has been some kind of cryptographic algorithm or a way to compute faster the congruences modulo $10^n$ of big numbers expressed as power towers, maybe. Just to give you a concrete application, we can know in a second how many digits of Graham's number are frozen, since it is a tetration base $3$ and $V(3)=1$.
Aug 8, 2022 at 2:03 comment added user44143 I find this too close to our Meta on how not to ask: “mathoverflow.net/help/dont-askl”. This could have multiple answers being equally valid; it lacks an actual problem to be solved; and the question is open-ended.
Aug 8, 2022 at 1:55 history edited Marco Ripà CC BY-SA 4.0
Removed redundant text; foxed typo
S Aug 8, 2022 at 0:58 review First questions
Aug 8, 2022 at 7:33
S Aug 8, 2022 at 0:58 history asked Marco Ripà CC BY-SA 4.0