Timeline for In Galois theory, why solvable groups must have their quotient groups be Abelian? [closed]
Current License: CC BY-SA 4.0
10 events
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| Aug 8, 2022 at 0:58 | comment | added | Gerry Myerson | Maybe OP would be satisfied with an explanation of "what makes algebraic radicals different from Bring radicals," but I agree that this website is not the appropriate place for such an explanation. | |
| Aug 7, 2022 at 12:03 | history | closed |
Friedrich Knop YCor Andreas Blass Chris Wuthrich Michael Albanese |
Not suitable for this site | |
| Aug 7, 2022 at 9:45 | review | Close votes | |||
| Aug 7, 2022 at 12:03 | |||||
| Aug 7, 2022 at 8:53 | answer | added | Peter Kropholler | timeline score: 1 | |
| Aug 7, 2022 at 8:05 | history | edited | YCor |
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| Aug 7, 2022 at 8:03 | comment | added | YCor | "one is that there must be a sequence of normal subgroups": no , this is not a constraint. Every group has a normal series. And your second "constraint" "the quotient groups between these sequences are Abelian groups" is senseless by itself, since it makes reference to the normal series of the "first constraint". So you should view the whole definition as a single constraint. | |
| Aug 7, 2022 at 7:39 | comment | added | KConrad | What do you mean by “the first one is well understood”? Did you try to read a proof in a Galois theory book that solvable equations (in characteristic 0) have solvable Galois groups? Or do you know why the splitting field of $x^n-a$ (in characteristic 0) has a solvable Galois group? | |
| Aug 7, 2022 at 7:07 | history | edited | Ray | CC BY-SA 4.0 |
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| S Aug 7, 2022 at 7:06 | review | First questions | |||
| Aug 7, 2022 at 11:38 | |||||
| S Aug 7, 2022 at 7:06 | history | asked | Ray | CC BY-SA 4.0 |