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Aug 12 at 1:41 vote accept lafes
Aug 4, 2022 at 22:05 comment added Michael Hardy The notation $\mathfrak{g}//G$ looks typographically weird and I changed it to $\mathfrak{g}/\!/G,$ coded as \mathfrak{g}/\!/G, but I notice that "skd" in an answer posted below was even more extreme and wrote $\mathfrak{g}/\!\!/G,$ coded as \mathfrak{g}/\!\!/G. (In URLs in LaTeX documents I've been known to write $\text{http:}/\!/\text{whatever.net}$ in preference to $\text{http:}//\text{whatever.net}$ $\qquad$
Aug 4, 2022 at 20:58 history edited Michael Hardy CC BY-SA 4.0
added 18 characters in body; edited title
Aug 4, 2022 at 11:42 answer added David E Speyer timeline score: 4
Aug 3, 2022 at 23:44 answer added skd timeline score: 16
Aug 3, 2022 at 22:37 comment added lafes @LSpice Thank you for your comment! Actually, I want to ask both cases all, any reductive $G$ and unipotent radicals $U$. So I appreciate any comments at least one of them and so your comment is very helpful for me. I will think about the case when $G$ is a torus. Thank you very much.
Aug 3, 2022 at 21:35 history edited LSpice CC BY-SA 4.0
Name of reference
Aug 3, 2022 at 21:33 comment added LSpice Is your question about reductive groups $G$, or about unipotent radicals $U$ of parabolic subgroups of reductive groups? The latter are unipotent, hence never reductive (unless they are trivial). Even for reductive groups $G$, one should expect that, though $\mathfrak g//G$ and $G//G$ are related, they will differ; consider the case where $G$ is a torus!
S Aug 3, 2022 at 21:28 review First questions
Aug 3, 2022 at 22:03
S Aug 3, 2022 at 21:28 history asked lafes CC BY-SA 4.0