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Aug 4, 2022 at 14:00 comment added Misha Verbitsky thanks! but how can this happen if the quotient $SL(2,R)/B_+$ is compact? Also, I would be very grateful for any reference to anything related to the stuff
Aug 4, 2022 at 0:18 comment added Moishe Kohan No Borel subgroup is not coarse equivalent to SL(2,R). Your conjecture is easily seen to be true for all real rank 1 Lie groups. It is most likely true in general as well.
Aug 3, 2022 at 21:27 history answered Misha Verbitsky CC BY-SA 4.0