Skip to main content
Notice removed Canonical answer required by CommunityBot
Bounty Ended with no winning answer by CommunityBot
removed capitals from title
Link
YCor
  • 63.9k
  • 5
  • 187
  • 286

Spectral problems with the wrong sign on the Poincaré Diskdisk

added 20 characters in body
Source Link
Bilateral
  • 2.8k
  • 22
  • 45

Let $\mathbb{D}$ denote the open unit disk in $\mathbb{C}$ equipped with the Poincaré metric $g$ of negative scalar curvature $-1$. Denote by $\Delta_g = \mathrm{Tr}_g(\nabla^g d) = - d^{\ast_g} d$ the Laplacian associated to $g$, where $\nabla^g$ is the Levi-Civita connection and $d^{\ast_g}$ is the formal adjoint of the exterior derivative with respect to the $L^2$ inner product determined by $g$. I am interested in the following spectral problem on $(\mathbb{D},g)$:

$$\Delta_g f = \mu^2 f + \kappa$$

where $\mu\in \mathbb{R}$, $f\in C^{\infty}(\mathbb{D})$, and $\kappa\in C^{\infty}(\mathbb{D})$ is a given fixed function. Note that in this problem the term $\mu^2 f$ has the "wrong sign" and therefore if $\kappa = 0$ (if I am not mistaken) then there are no $L^2$ integrable solutions. On the other hand, if $\kappa \neq 0$, since $\mu^2$ does not belong to the essential spectrum of $\Delta_g$, the resolvent is well-defined and we can always find a solution that is in addition unique. Is this correct? Can this resolvent be computed for functions that are not $L^2$ integrable?

I am interested in this spectral problem beyond $L^2$ integrable functions. I have found a lot of information for the same spectral problem but with the "right sign" and $L^2$ solutions. I wonder, what is known about the case with the "wrong sign"? Any pointer to the literature will be highly appreciated.

Let $\mathbb{D}$ denote the open unit disk in $\mathbb{C}$ equipped with the Poincaré metric $g$ of negative scalar curvature $-1$. Denote by $\Delta_g = \mathrm{Tr}_g(\nabla^g d) = - d^{\ast_g} d$ the Laplacian associated to $g$, where $\nabla^g$ is the Levi-Civita connection and $d^{\ast_g}$ is the formal adjoint of the exterior derivative with respect to the $L^2$ inner product determined by $g$. I am interested in the following spectral problem on $(\mathbb{D},g)$:

$$\Delta_g f = \mu^2 f + \kappa$$

where $\mu\in \mathbb{R}$, $f\in C^{\infty}(\mathbb{D})$, and $\kappa\in C^{\infty}(\mathbb{D})$ is a given fixed function. Note that in this problem the term $\mu^2 f$ has the "wrong sign" and therefore if $\kappa = 0$ (if I am not mistaken) then there are no $L^2$ integrable solutions. On the other hand, if $\kappa \neq 0$, since $\mu^2$ does not belong to the essential spectrum of $\Delta_g$, the resolvent is well-defined and we can always find a solution that is in addition unique. Is this correct? Can this resolvent be computed for functions that are not $L^2$ integrable?

I am interested in this spectral problem beyond $L^2$ integrable functions. I have found a lot of information for the same spectral problem but with the "right sign". I wonder, what is known about the case with the "wrong sign"? Any pointer to the literature will be highly appreciated.

Let $\mathbb{D}$ denote the open unit disk in $\mathbb{C}$ equipped with the Poincaré metric $g$ of negative scalar curvature $-1$. Denote by $\Delta_g = \mathrm{Tr}_g(\nabla^g d) = - d^{\ast_g} d$ the Laplacian associated to $g$, where $\nabla^g$ is the Levi-Civita connection and $d^{\ast_g}$ is the formal adjoint of the exterior derivative with respect to the $L^2$ inner product determined by $g$. I am interested in the following spectral problem on $(\mathbb{D},g)$:

$$\Delta_g f = \mu^2 f + \kappa$$

where $\mu\in \mathbb{R}$, $f\in C^{\infty}(\mathbb{D})$, and $\kappa\in C^{\infty}(\mathbb{D})$ is a given fixed function. Note that in this problem the term $\mu^2 f$ has the "wrong sign" and therefore if $\kappa = 0$ (if I am not mistaken) then there are no $L^2$ integrable solutions. On the other hand, if $\kappa \neq 0$, since $\mu^2$ does not belong to the essential spectrum of $\Delta_g$, the resolvent is well-defined and we can always find a solution that is in addition unique. Is this correct? Can this resolvent be computed for functions that are not $L^2$ integrable?

I am interested in this spectral problem beyond $L^2$ integrable functions. I have found a lot of information for the same spectral problem but with the "right sign" and $L^2$ solutions. I wonder, what is known about the case with the "wrong sign"? Any pointer to the literature will be highly appreciated.

Notice added Canonical answer required by Bilateral
Bounty Started worth 400 reputation by Bilateral
Displaying displayed equation; deleted "thanks"
Source Link
LSpice
  • 12.9k
  • 4
  • 45
  • 69

Let $\mathbb{D}$ denote the open unit disk in $\mathbb{C}$ equipped with the Poincaré metric $g$ of negative scalar curvature $-1$. Denote by $\Delta_g = \mathrm{Tr}_g(\nabla^g d) = - d^{\ast_g} d$ the Laplacian associated to $g$, where $\nabla^g$ is the Levi-Civita connection and $d^{\ast_g}$ is the formal adjoint of the exterior derivative with respect to the $L^2$ inner product determined by $g$. I am interested in the following spectral problem on $(\mathbb{D},g)$:

$\Delta_g f = \mu^2 f + \kappa$$$\Delta_g f = \mu^2 f + \kappa$$

where $\mu\in \mathbb{R}$, $f\in C^{\infty}(\mathbb{D})$, and $\kappa\in C^{\infty}(\mathbb{D})$ is a given fixed function. Note that in this problem the term $\mu^2 f$ has the "wrong sign" and therefore if $\kappa = 0$ (if I am not mistaken) then there are no $L^2$ integrable solutions. On the other hand, if $\kappa \neq 0$, since $\mu^2$ does not belong to the essential spectrum of $\Delta_g$, the resolvent is well-defined and we can always find a solution that is in addition unique. Is this correct? Can this resolvent be computed for functions that are not $L^2$ integrable?

I am interested in this spectral problem beyond $L^2$ integrable functions. I have found a lot of information for the same spectral problem but with the "right sign". I wonder, what is known about the case with the "wrong sign"? Any pointer to the literature will be highly appreciated.

Thanks.

Let $\mathbb{D}$ denote the open unit disk in $\mathbb{C}$ equipped with the Poincaré metric $g$ of negative scalar curvature $-1$. Denote by $\Delta_g = \mathrm{Tr}_g(\nabla^g d) = - d^{\ast_g} d$ the Laplacian associated to $g$, where $\nabla^g$ is the Levi-Civita connection and $d^{\ast_g}$ is the formal adjoint of the exterior derivative with respect to the $L^2$ inner product determined by $g$. I am interested in the following spectral problem on $(\mathbb{D},g)$:

$\Delta_g f = \mu^2 f + \kappa$

where $\mu\in \mathbb{R}$, $f\in C^{\infty}(\mathbb{D})$, and $\kappa\in C^{\infty}(\mathbb{D})$ is a given fixed function. Note that in this problem the term $\mu^2 f$ has the "wrong sign" and therefore if $\kappa = 0$ (if I am not mistaken) then there are no $L^2$ integrable solutions. On the other hand, if $\kappa \neq 0$, since $\mu^2$ does not belong to the essential spectrum of $\Delta_g$, the resolvent is well-defined and we can always find a solution that is in addition unique. Is this correct? Can this resolvent be computed for functions that are not $L^2$ integrable?

I am interested in this spectral problem beyond $L^2$ integrable functions. I have found a lot of information for the same spectral problem but with the "right sign". I wonder, what is known about the case with the "wrong sign"? Any pointer to the literature will be highly appreciated.

Thanks.

Let $\mathbb{D}$ denote the open unit disk in $\mathbb{C}$ equipped with the Poincaré metric $g$ of negative scalar curvature $-1$. Denote by $\Delta_g = \mathrm{Tr}_g(\nabla^g d) = - d^{\ast_g} d$ the Laplacian associated to $g$, where $\nabla^g$ is the Levi-Civita connection and $d^{\ast_g}$ is the formal adjoint of the exterior derivative with respect to the $L^2$ inner product determined by $g$. I am interested in the following spectral problem on $(\mathbb{D},g)$:

$$\Delta_g f = \mu^2 f + \kappa$$

where $\mu\in \mathbb{R}$, $f\in C^{\infty}(\mathbb{D})$, and $\kappa\in C^{\infty}(\mathbb{D})$ is a given fixed function. Note that in this problem the term $\mu^2 f$ has the "wrong sign" and therefore if $\kappa = 0$ (if I am not mistaken) then there are no $L^2$ integrable solutions. On the other hand, if $\kappa \neq 0$, since $\mu^2$ does not belong to the essential spectrum of $\Delta_g$, the resolvent is well-defined and we can always find a solution that is in addition unique. Is this correct? Can this resolvent be computed for functions that are not $L^2$ integrable?

I am interested in this spectral problem beyond $L^2$ integrable functions. I have found a lot of information for the same spectral problem but with the "right sign". I wonder, what is known about the case with the "wrong sign"? Any pointer to the literature will be highly appreciated.

added 16 characters in body
Source Link
Bilateral
  • 2.8k
  • 22
  • 45
Loading
Source Link
Bilateral
  • 2.8k
  • 22
  • 45
Loading