Timeline for On odd perfect numbers and a GCD - Part III
Current License: CC BY-SA 4.0
15 events
| when toggle format | what | by | license | comment | |
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| Apr 12, 2023 at 14:53 | vote | accept | Jose Arnaldo Bebita | ||
| Apr 12, 2023 at 14:51 | history | edited | Jose Arnaldo Bebita | CC BY-SA 4.0 |
streamlined previous answer, corrected mistakes
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| Apr 12, 2023 at 14:26 | history | undeleted | Jose Arnaldo Bebita | ||
| Aug 14, 2022 at 14:26 | history | deleted | Jose Arnaldo Bebita | via Vote | |
| Jul 27, 2022 at 2:59 | history | edited | Jose Arnaldo Bebita | CC BY-SA 4.0 |
added 104 characters in body
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| Jul 27, 2022 at 2:51 | history | edited | Jose Arnaldo Bebita | CC BY-SA 4.0 |
changed the index $i$ to $j$ in the proof (to fix the minor error in the logic)
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| Jul 27, 2022 at 1:44 | vote | accept | Jose Arnaldo Bebita | ||
| Aug 14, 2022 at 14:26 | |||||
| Jul 27, 2022 at 1:20 | history | edited | Jose Arnaldo Bebita | CC BY-SA 4.0 |
added 11 characters in body
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| Jul 27, 2022 at 1:13 | history | edited | Jose Arnaldo Bebita | CC BY-SA 4.0 |
added 1023 characters in body
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| Jul 27, 2022 at 0:48 | comment | added | Jose Arnaldo Bebita | Thank you for your suggestion, @LSpice! Incorporating these changes in the post now. | |
| Jul 27, 2022 at 0:35 | comment | added | LSpice |
A suggestion: the huge parentheses might be easier to read with \big rather than \Bigg; for example, $\dfrac{\gcd\bigl(n\sigma(n^2), i(q)\bigr)}{i(q)}$ \dfrac{\gcd\bigl(n\sigma(n^2), i(q)\bigr)}{i(q)} rather than $\dfrac{\gcd\Biggl(n\sigma(n^2), i(q)\Biggr)}{i(q)}$ \dfrac{\gcd\Biggl(n\sigma(n^2), i(q)\Biggr)}{i(q)}.
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| Jul 27, 2022 at 0:34 | history | edited | LSpice | CC BY-SA 4.0 |
Missing parenthesis; mild TeX
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| Jul 27, 2022 at 0:07 | history | edited | Jose Arnaldo Bebita | CC BY-SA 4.0 |
added 5 characters in body
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| Jul 26, 2022 at 23:52 | history | edited | Jose Arnaldo Bebita | CC BY-SA 4.0 |
added context
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| Jul 26, 2022 at 23:46 | history | answered | Jose Arnaldo Bebita | CC BY-SA 4.0 |