Timeline for Distance among integer set
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
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| Jul 18, 2022 at 9:34 | comment | added | Seva | @huicj: $A$ is assumed to satisfy $|A-A|\le2|A|-1$, and $|A|=|A_0|+1$. Thus, $|A-A|-2\le2|A|-3=2|A_0|-1$. | |
| Jul 18, 2022 at 8:19 | comment | added | hui cj | How can we get $|A-A|-2 \leq 2|A_0|-1$? | |
| Jul 18, 2022 at 7:48 | comment | added | Seva | @huicj: I tried to explain that part of the (first) proof, hope is clear now. | |
| Jul 18, 2022 at 7:47 | history | edited | Seva | CC BY-SA 4.0 |
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| Jul 18, 2022 at 7:23 | comment | added | hui cj | The second one is clear to comprehend. I know what "Moreover, if A0 is a progression (the induction hypotheses), while A is not, then (A−A)∖(A0−A0) additionally contains the elements ±(an−a2)." means, but I still confused about how to deduce A is an arithmetic progression. Maybe I think we should demonstrate $⊆$ in $(A0−A0)∪{an−a1,a1−an}⊆A−A$ is equivalent to $=$? Can you expand a little about this? Thanks again! | |
| Jul 18, 2022 at 6:23 | history | edited | Seva | CC BY-SA 4.0 |
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| Jul 17, 2022 at 19:15 | comment | added | Seva | @huicj: $|S|$ is the number of elements of the set $S$. I updated the answer to address your second question. | |
| Jul 17, 2022 at 19:14 | history | edited | Seva | CC BY-SA 4.0 |
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| Jul 17, 2022 at 16:59 | comment | added | hui cj | Sorry, I can not figure out the what note | | means in your proof, and why the last equation means only arithmetic progression could be the answer? | |
| Jul 17, 2022 at 16:15 | comment | added | hui cj | Thanks, that is exactly what I want to know! | |
| Jul 17, 2022 at 15:46 | history | answered | Seva | CC BY-SA 4.0 |