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Jul 16, 2022 at 23:19 comment added paul garrett If I were tasked with understanding this, I'd use the UFD-ness of $\mathbb Z[x_1,\ldots,x_n]$ and/or $\mathbb C[x_1,\ldots,x_n]$, and make adroit choices of values of the $x$'s to get vanishing, ... much as we do for Vandermonde.
Jul 16, 2022 at 21:29 history edited LSpice CC BY-SA 4.0
`\eqref`, and `\cdots` and `\ddots` in matrices
Jul 16, 2022 at 21:14 history edited T. Amdeberhan CC BY-SA 4.0
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Jul 16, 2022 at 19:49 comment added Wolfgang Sure that these are beautiful cyclic patterns. But if even for $n=3$, the determinant doesn't seem to allow any kind of decomposition and the discriminant is as it is, there won't be a lot of hope. Unless you can find "nice" eigenvectors, but even for e.g. $(x_1,x_2,x_3)=(1,2,4)$ there is nothing nice... :(
Jul 16, 2022 at 17:09 history edited T. Amdeberhan CC BY-SA 4.0
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Jul 16, 2022 at 17:07 comment added user61318 Not sure what one can say from three examples. What do you mean by more experimentation? What did it reveal? Do you expect a nice answer merely because of the circulant case? In fact, why stop at the Vandermonde determinant. Take alternants with exponents of the form $\lambda_i+n-i$.
Jul 16, 2022 at 16:38 history edited T. Amdeberhan CC BY-SA 4.0
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Jul 16, 2022 at 15:28 history asked T. Amdeberhan CC BY-SA 4.0