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Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
S Oct 20, 2010 at 1:25 vote accept John Craighead
S Oct 20, 2010 at 1:24 vote accept John Craighead
S Oct 20, 2010 at 1:25
S Oct 20, 2010 at 1:24 vote accept John Craighead
S Oct 20, 2010 at 1:24
Oct 20, 2010 at 1:24 vote accept John Craighead
S Oct 20, 2010 at 1:24
Oct 19, 2010 at 0:29 answer added Faisal timeline score: 14
Oct 18, 2010 at 22:45 comment added Victor Protsak There are many more abelian subgroups of $GL(n,R),$ for example, all conjugates of $A,$ but also e.g. the block upper triangular matrices of the form $$\begin{pmatrix}I_k & *\\ 0 & I_{n-k}\end{pmatrix}$$ The correct formulation is that $A$ is a maximal connected diagonalizable subgroup.
Oct 18, 2010 at 17:42 history edited Jim Humphreys CC BY-SA 2.5
added 112 characters in body
Oct 18, 2010 at 17:25 answer added Jim Humphreys timeline score: 11
Oct 18, 2010 at 15:11 history asked John Craighead CC BY-SA 2.5