$\newcommand{\cD}{\mathcal{D}}\newcommand{\cX}{\mathcal{X}}$Let(This is a slight rephrasing and modification of the original question)
Let $D\subset\mathbb{C}$ be the complex unit disk. ForLet $X$ be a family of prestable curvescompact complex manifold, fibered over $D$ which is smooth overin relative dimension 1. Assume the fibers above $D^* := D - 0$ are smooth, but whose centraland the fiber may have nodesabove 0 has at worst ordinary double points (nodes) as singularities. For any $\eta\in D^*$, associated to each node $x\in X_0$ is a vanishing cycle $v_x\in H_1(X_\eta)$, and the Picard-Lefschetz formula describes precisely the monodromy action of a generator $\pi_1(D^*)$$\gamma\in\pi_1(D^*,\eta)$ on the homology of a smooth fiber$H_1(X_\eta)$ in terms of the vanishing cycles $v_x$. I'm looking for an analogous formula in the case whereIn particular, if $\varphi$ is the central fiber may have stacky structuremonodromy representation, then $\varphi(\gamma)$ is unipotent.
Precisely, let $\cD := [D/\mu_n]$ be the stack quotient by the order $n$ cyclic group of rotationsLet $\mu_n$. Thus $\cD$ is topologically also a unit disk, but whose center has be a cyclic automorphism group of order $n$. The canonical map acting by rotations on $D\rightarrow\cD$ is a universal cover$D$. LetSuppose that this action on $f : \cX\rightarrow\cD$ be a family of prestable curves$D$ lifts to an action on -- by this I mean that if$X$ $f_D : X := \cX_D\rightarrow D$ denotes the base change of(in particular it acts on $f$ to$X_0$). Let $D$$X^* := X - X_0$, then $f_D$$X^*/\mu_n\rightarrow D^*/\mu_n$ is a family of prestablesmooth curves inover a punctured disk, and if $\eta'$ denotes the usual senseimage of (i.e., fibers have at worst nodal singularities). In particular$\eta$, there is anthen we may again ask about the monodromy action of a generator $\mu_n$$\gamma'\in\pi_1(D^*/\mu_n,\eta')$ on $X := \cX_D$$H_1(X_\eta)$. Abusing notation, again let $f_D$ is equivariant for this action, and$\varphi$ denote the monodromy representation. Let $\cX \cong [X/\mu_n]$$\varphi(\gamma') = SU$ (so the only stackiness forsay, viewed in $\cX$ is along$\text{GL}(H_1(X_\eta,\mathbb{C}))$ be the central fiber). We further assume that $X$ is smooth overJordan-Chevalley decomposition, so $\mathbb{C}$$S$ commutes with (i.e.$U$, $X$$S$ is a complex manifold)semisimple, and the fibers of $X$ over $D^* - 0$ are smooth. The central fiber $X_0$ may have multiple nodes$U$ is unipotent.
LetBy comparison with the situation over $\cD^* := \cD - 0$$D$, we know that $$\varphi(\gamma'^n) = \varphi(\gamma)$$ which forces $\cX^* := \cX - \cX_0$,$S^n = 1$ and $b\in\cD^*$. Then $\cX^*\rightarrow\cD^*$ is a topologically trivial fibration over a punctured disk$U^n = \varphi(\gamma)$, so it$U$ is natural to ask about the monodromy action ofunique unipotent $\pi_1(\cD^*,b)$ on$n$th root of $H_1(\cX_b)$$\varphi(\gamma)$.
If $b'\in D^* := D - 0$ is a lift of $b$, then $H_1(X_{b'})\cong H_1(\cX_b)$ canonically, and the Picard-Lefschetz formula describes the monodromy action of $\pi_1(D^*,b')$$\mu_n$ acts freely on $H_1(X_{b'}) = H_1(\cX_b)$ in terms of intersections with vanishing cycles. In particularthe nodes, ifthen $\gamma\in\pi_1(\cD^*,b)$$X/\mu_n$ is again a generatormanifold, thenso applying Picard-Lefschetz directly to $f_D : X\rightarrow D$ gives the action of$X/\mu_n$, we find that $\gamma^n$$\varphi(\gamma')$ is unipotent, so $S = 1$.
Is there a "Picard-Lefschetz formula" forMy question concerns the monodromy action ofcase where $\gamma$? If possible I'd like$\mu_n$ fixes the answer to be in terms of vanishing cyclesnodes, and possibly information aboutalso preserves the action of $\mu_n$ on $X_0$ andbranches at every node. In this case, how can we relate the tangent spaces insemisimple part $X$$S$ of points in $X_0$. I'm happy$\varphi(\gamma')$ to assume thatinformation about how $\mu_n$ acts freely on the nodes of $X_0$.
(Edited to assume the nodes have trivial stabilizers)?