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Jul 3, 2022 at 6:52 comment added Anthony Quas Doesn't $\bar\pi$ send any rotationally-symmetric measure to itself? If so, it's immediate that $\bar\pi$ is surjective.
Jul 2, 2022 at 19:45 comment added Anthony Quas My mistake. I somehow thought you were talking about the unit sphere. But in that case, aren’t measures completely described by the radial measure?
Jul 1, 2022 at 16:11 comment added Drew Brady I don't think so. For instance a Gaussian truncated to the unit ball places much more mass near the origin than the Lebesgue (i.e., uniform) measure does, no?
Jul 1, 2022 at 16:10 comment added Anthony Quas I think that’s also Lebesgue?
Jul 1, 2022 at 15:50 comment added Drew Brady There are other measures, in general, which are rotation invariant, right? For instance, a (truncated) Gaussian with identity covariance.
Jun 30, 2022 at 1:25 comment added Anthony Quas Isn’t Lebesgue measure the unique rotation-invariant measure up to scaling? If that’s so, the map $\bar\pi$ should be pretty easy to describe.
Jun 29, 2022 at 22:46 history asked Drew Brady CC BY-SA 4.0