Timeline for How to solve for $a$ in $\sum_{j=i}^n (a -j) \binom{n}{j} y^j (1-y)^{n-j} = 0$
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 29, 2022 at 18:43 | vote | accept | E. Turok | ||
| Jun 26, 2022 at 22:01 | comment | added | Carlo Beenakker | $_2F_1$ is the Gauss hypergeometric function; this is how Mathematica evaluates your series. | |
| Jun 26, 2022 at 21:30 | comment | added | E. Turok | Can you explain how you obtained this solution? Also, can you clarify what $F_1$ is? | |
| Jun 26, 2022 at 21:27 | history | answered | Carlo Beenakker | CC BY-SA 4.0 |