Timeline for Linear system with +-1 coefficients and three variables for each equation
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 28, 2022 at 7:58 | comment | added | Gerry Myerson | The maximum value probably depends on how you implement the substitution method. | |
| Jun 28, 2022 at 4:23 | comment | added | Mario Giambarioli | Suppose that the linear system has $a$ variables and $a$ linear indipendent equations. Thia means that we can find the value of each variable of $LS$. Suppose we solve $LS$ by substitution, what is the max value of the coefficients of the equations that we get by the substitution method soution of $LS$? | |
| Jun 26, 2022 at 22:48 | comment | added | Gerry Myerson | Yes, but you also have $x_a=x_b-x_c+1$, $x_b=x_a+x+c-1$, $x_c=x_b-x_a+1$, $x_d=x_b-x_c+1$, and $x_e=x_a+x_d-1$, all with $k_{\rm max}=1$. So, what is it that you really want? | |
| Jun 26, 2022 at 14:51 | comment | added | Mario Giambarioli | We have a linear system, therefore we have more than only one equation. For example, if we have $x_{a}-x_{b}+x_{c}=1$, $x_{d}-x_{b}+x_{c}=1$ and $-x_{a}-x_{d}+x_{e}= -1$, we have $x_{c}=2x_{a}-1$. | |
| Jun 26, 2022 at 12:21 | comment | added | Gerry Myerson | From $x_a-x_b+x_c=p$ you get $x_a=x_b-x_c+p$ so you can take $k_{\rm max}=1$, right? | |
| Jun 26, 2022 at 6:18 | history | asked | Mario Giambarioli | CC BY-SA 4.0 |