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Feb 8, 2023 at 7:02 comment added Nate Eldredge I recently stumbled on another "nuke" proof of Perron-Frobenius. Let's do the case where the matrix $A$ is stochastic. Fix a Banach limit (!!!), $\Phi \in (\ell^\infty)^*$. Apply $\Phi$ element-wise to the sequence of (stochastic) matrices $A, A^2, A^3, \dots$, and let $B$ be the $\Phi$-limit. By the linearity and positivity of $\Phi$, $B$ is stochastic. By the linearity and shift invariance, $BA=B$. So each row of $B$ is a non-negative eigenvector of the eigenvalue 1.
Oct 17, 2010 at 22:46 history edited JBL CC BY-SA 2.5
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Oct 17, 2010 at 21:41 comment added Tom Smith "Flamed", not "fired"!
Oct 17, 2010 at 20:07 comment added Denis Serre I mean that someone wrote a nasty review because of that.
Oct 17, 2010 at 19:36 comment added The Mathemagician And they fired you for this? OoOoOo,they would have been SO sued...
Oct 17, 2010 at 19:07 history answered Denis Serre CC BY-SA 2.5