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Apr 27, 2023 at 14:49 comment added Dmitri Pavlov @lvl: Kan's Ex^∞ does not preserve infinite products. For this reason, neither does this functor. Of course, Ex^∞ is also not a right adjoint functor.
Apr 27, 2023 at 6:33 comment added display llvll is this functor right adjoint to something?
Apr 27, 2023 at 6:17 comment added display llvll Nice answer. I was wondering, does this functor preserve all limits (and enjoys the other good properties) as Kan’s Ex_infty ?
Jun 22, 2022 at 18:23 history answered Dmitri Pavlov CC BY-SA 4.0