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Jun 24, 2022 at 14:44 comment added Iosif Pinelis @GregZitelli : This depends on how fast (in $n$) the convergence to $\mu^m$ is, for each $m$.
Jun 24, 2022 at 14:33 comment added Greg Zitelli I wonder if it's possible to say more, since E(Z^m) -> E(Z)^m behaves as a constant.
Jun 24, 2022 at 14:31 vote accept Greg Zitelli
Jun 22, 2022 at 9:02 history edited Davide Giraudo CC BY-SA 4.0
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Jun 22, 2022 at 0:32 history edited Iosif Pinelis CC BY-SA 4.0
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Jun 22, 2022 at 0:27 history answered Iosif Pinelis CC BY-SA 4.0