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Nov 17, 2010 at 14:20 vote accept Alexander Braverman
Nov 17, 2010 at 14:20 vote accept Alexander Braverman
Nov 17, 2010 at 14:20
Oct 30, 2010 at 17:02 history edited Torsten Ekedahl CC BY-SA 2.5
added 35 characters in body
Oct 30, 2010 at 7:34 history edited Torsten Ekedahl CC BY-SA 2.5
Added one more elaboration
Oct 29, 2010 at 11:51 comment added Alexander Braverman Thank you. My question is now kind of informal: what kind of conditions can one put on a variety so that the answer will be positive? The point is that the varieties I have in mind are very specific and I can probably prove many things about them if I only knew what to prove...
Oct 18, 2010 at 20:50 comment added Qing Liu By the definition of $K_0$, the class of $X$ only sees the "piece-wise geometry" of $X$: if $X$ and $Y$ are two varieties such that they can be stratified into locally closed subsets $X_1,...,X_n$ and $Y_1,..., Y_n$ with $X_i$ isomorphic to $Y_i$, then $[X]=[Y]$. The converse is a question of Larsen and Luntz. It is true over $\mathbb C$ if $X$ contains only finitely many rational curves (see Q.L & J. Sebag: {\it The Grothendieck ring of varieties and piecewise isomorphisms}, Math. Z., {\bf 265} (2010), 321-342, Theorem 5). But this is orthogonal to your situation.
Oct 17, 2010 at 15:12 history edited Torsten Ekedahl CC BY-SA 2.5
Added further discussion on smooth quadrics
Oct 17, 2010 at 14:29 comment added Alexander Braverman Thank you! Do you know if there is a way to put stronger conditions on $X$, so that the answer will be "yes"?
Oct 17, 2010 at 14:21 history answered Torsten Ekedahl CC BY-SA 2.5