Timeline for Ways to prove the fundamental theorem of algebra
Current License: CC BY-SA 2.5
3 events
| when toggle format | what | by | license | comment | |
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| May 28, 2018 at 23:57 | comment | added | Jeff Strom | @AliTaghavi Because $\mathbb{H}$ is not commutative, you can't always collect all the terms of the form $a_0q a_1 q a_2\cdots a_{n-1}q a_n$ (with $a\in \mathbb{H}$) into a single term of the form $a q^n$. | |
| May 28, 2018 at 7:27 | comment | added | Ali Taghavi | What do you mean by "provided it has only one highest degree"? do you mean the highest term would not be in the form $aq^n+q^nb$? What can be said about such kind polynomials?Do they have always roots? | |
| Oct 17, 2010 at 13:54 | history | answered | Jeff Strom | CC BY-SA 2.5 |