Skip to main content
Bumped by Community user
removed capitals from title, added tag
Link
YCor
  • 63.9k
  • 5
  • 187
  • 286

Non-Analytically Measurable Setanalytically measurable set in $\Delta^1_2$

added 4 characters in body
Source Link

I'm wondering if there is some reference you may know that gives an explicit set which is not analytically-measurable (i.e., not in the sigma-algebra generated by $\Sigma^1_1$), notbut which is not in $\Delta^1_2$? I can prove that such a set exists but just wondering if there's a (fairly) concrete example.

I'm wondering if there is some reference you may know that gives an explicit set which is analytically-measurable (i.e., in the sigma-algebra generated by $\Sigma^1_1$), not which is not in $\Delta^1_2$? I can prove that such a set exists but just wondering if there's a (fairly) concrete example.

I'm wondering if there is some reference you may know that gives an explicit set which is not analytically-measurable (i.e., not in the sigma-algebra generated by $\Sigma^1_1$), but which is in $\Delta^1_2$? I can prove that such a set exists but just wondering if there's a (fairly) concrete example.

Source Link

Non-Analytically Measurable Set in $\Delta^1_2$

I'm wondering if there is some reference you may know that gives an explicit set which is analytically-measurable (i.e., in the sigma-algebra generated by $\Sigma^1_1$), not which is not in $\Delta^1_2$? I can prove that such a set exists but just wondering if there's a (fairly) concrete example.