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Jun 18, 2022 at 21:38 history edited David Lampert CC BY-SA 4.0
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Jun 18, 2022 at 21:32 comment added David Lampert @PaceNielsen You are right, I sloppily had thought $y_1-1$ was pure grade but this is wrong. I think we can salvage something by changing $\mathbb{Q}$ to $\mathbb{F}_2$ and using $\mathbb{Q}$-grading instead of $\mathbb{N}$-grading but that wouldn't answer the original question.
Jun 18, 2022 at 21:29 history edited David Lampert CC BY-SA 4.0
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Jun 18, 2022 at 19:24 comment added Pace Nielsen David, I don't understand how the embedding in $\mathbb{Q}[[x]]$ gives $R$ an $\mathbb{N}$-grading. For example, what are the finitely many graded components of $y_1$?
Jun 18, 2022 at 18:44 comment added It'sMe My follow-up question is- can we find a counter example where the ring is a quotient of a polynomial ring in finitely many variables, over algebraically closed field?
Jun 18, 2022 at 18:39 history answered David Lampert CC BY-SA 4.0