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Jun 13, 2022 at 15:50 vote accept RandomMatrices
Jun 13, 2022 at 6:28 history edited Carlo Beenakker CC BY-SA 4.0
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Jun 13, 2022 at 6:23 comment added Carlo Beenakker certainly, the expected value of $U^p$ is the identity matrix.
Jun 13, 2022 at 4:21 comment added RandomMatrices To sanity check, the expected value of $U^{p}(n)$, over the Haar measure, should still be the $n \times n$ identity matrix (it is just a tensor product of $p$ identity matrices of suitable dimensions), is that correct?
Jun 12, 2022 at 22:14 history edited Carlo Beenakker CC BY-SA 4.0
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Jun 12, 2022 at 22:02 history edited Carlo Beenakker CC BY-SA 4.0
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Jun 12, 2022 at 21:53 history answered Carlo Beenakker CC BY-SA 4.0