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Jun 2, 2022 at 15:43 comment added Basics Great! Thanks for the quick answer!
Jun 2, 2022 at 15:35 comment added abx To give a concrete example: a hypersurface of degree $(2,2,2)$ in $\mathbb{P}^1\times \mathbb{P}^1\times \mathbb{P}^1$ contains a subgroup $G$ isomorphic to the free product of 3 groups of order 2 , hence containing infinitely many elements of order 2.
Jun 2, 2022 at 15:34 comment added Basics Cojugating by a commuting element does not give a new automorphim. It is unclear to me that conjugating shall give infinitely many different automorphisms.
Jun 2, 2022 at 15:15 comment added Will Sawin Does conjugating a finite order automorphism by every element of an infinite automorphism group not do the trick?
Jun 2, 2022 at 15:14 history asked Basics CC BY-SA 4.0