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May 31, 2022 at 20:58 comment added Wojowu @fedja That's a good point! I tried some explicit constructions of that sort by taking $n$ to have a small prime factor, but I didn't think to try and make $2n-P$ hit a specific residue class in general! I have added a note to the answer to acknowledge this.
May 31, 2022 at 20:58 history edited Wojowu CC BY-SA 4.0
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May 31, 2022 at 20:47 comment added fedja Just notice that a "product $P$ of small primes" can be anything you want modulo any particular number, so $2n-P$ can be always made divisible by $30$, say, and your proof shows that, indeed, there are only finitely many such $n$ :-)
May 31, 2022 at 19:58 history answered Wojowu CC BY-SA 4.0