Timeline for About a recent paper of Rickard on finitistic dimension
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
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| Dec 10, 2022 at 10:35 | comment | added | Jeremy Rickard | @theL Although it may not technically be Nakayama's lemma, it's still true for finite dimensional algebras that if $M\otimes_AA/\operatorname{rad}A=0$ then $M=0$, even if $M$ is not finitely generated. | |
| Nov 23, 2022 at 20:00 | comment | added | the L | @MarianoSuárez-Álvarez can you really use Nakayama? the modules here are not finitely generated. | |
| Jun 11, 2022 at 10:04 | history | edited | David White | CC BY-SA 4.0 |
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| May 30, 2022 at 23:16 | comment | added | Mariano Suárez-Álvarez | It is slightly simpler to just take a minimal resolution of M and tensor it with A/radA: the differentials of the resulting complex are all zero, and the modules nonzero because of Nakayama. | |
| May 30, 2022 at 17:44 | vote | accept | Reading finitisitic | ||
| May 30, 2022 at 17:37 | history | answered | Mare | CC BY-SA 4.0 |