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May 30, 2022 at 9:25 comment added Tobias Fritz @Aurel, of course, sorry, I'll delete my comment. Then I don't know.
May 30, 2022 at 8:13 comment added Aurel @TobiasFritz Really? For $G$ an oriented triangle (edges $1\to 2$, $2\to 3$ and $3\to 1$), $G\cap G^{op}$ is the graph with $3$ vertices and no edges, but $G$ has a single strongly connected component. Am I missing something?
May 29, 2022 at 20:32 vote accept Arrow
May 29, 2022 at 20:32 comment added Arrow Do you see any way of defining strongly connected components using the connected components functor and some other "canonical" constructions?
May 29, 2022 at 18:00 history answered Tobias Fritz CC BY-SA 4.0