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May 29, 2022 at 6:06 vote accept Antoine Labelle
May 28, 2022 at 14:33 answer added Antoine Labelle timeline score: 1
May 27, 2022 at 12:18 comment added Antoine Labelle I think you're right, I got confused. The union bound couldn't work for the first version of the question because of factors of $\varepsilon$, but I think it might work here, thought I have to think that through.
May 27, 2022 at 10:49 comment added Fedor Petrov Why is union bound so bad? On the first glance, the guy $E(A,B)-k|A|\cdot |B|/n$ behaves as normal with variance $kn$, so the probability of the deviation of order $kn$ is exponential in $kn$ that should be enough.
S May 27, 2022 at 10:14 history suggested Zach Hunter CC BY-SA 4.0
Grammar fix
May 27, 2022 at 9:46 review Suggested edits
S May 27, 2022 at 10:14
May 26, 2022 at 23:49 history asked Antoine Labelle CC BY-SA 4.0