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Sep 12, 2022 at 11:54 comment added Jochen Glueck Today I happened to find a simple counterexample which shows that $Q(E)$ is not always convex: let $E = \mathbb{R}^2$ and $F = \mathbb{R}^{2 \times 2}$, and let $B(x,y) = xy^{\operatorname{T}}$ for all $x,y \in E$. Then the range of $Q$ is the set of the symmetric matrices of rank $\le 1$, which is not convex.
Jun 2, 2022 at 20:38 comment added Jochen Glueck Thanks for your response!
Jun 2, 2022 at 20:32 comment added Eduardo Longa I didn't found out :( but I suspect it may not be always convex
May 26, 2022 at 17:28 comment added Jochen Glueck May I ask whether you found out whether $Q(E)$ is always convex?
May 25, 2022 at 6:24 history became hot network question
May 25, 2022 at 1:22 vote accept Eduardo Longa
May 25, 2022 at 0:16 answer added Jochen Glueck timeline score: 7
May 25, 2022 at 0:11 comment added Jochen Glueck I'll post a counterexample. But in fact, I'm quite confused about the convexity now. (Probably because I should actually sleep rather than doing maths...)
May 25, 2022 at 0:09 history edited Eduardo Longa
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May 25, 2022 at 0:08 comment added Eduardo Longa Really? Do you have a counterexample in mind? What if the norms are induced by an inner product?
May 24, 2022 at 22:40 history edited Eduardo Longa CC BY-SA 4.0
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May 24, 2022 at 22:24 history asked Eduardo Longa CC BY-SA 4.0