Timeline for First Dirichlet eigenvalue on regular polygons
Current License: CC BY-SA 4.0
13 events
| when toggle format | what | by | license | comment | |
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| Dec 10 at 13:22 | comment | added | Beni Bogosel | @Héhéhé: If we're talking about Dirichlet eigenvalues the tangential derivative of the eigenfunction is zero, since it is constant in the tangential direction. The norm of the gradient or the normal derivative gives the same thing. | |
| Dec 10 at 13:21 | answer | added | Beni Bogosel | timeline score: 0 | |
| May 26, 2022 at 10:01 | vote | accept | guest61 | ||
| May 26, 2022 at 13:20 | |||||
| May 24, 2022 at 19:25 | history | became hot network question | |||
| May 24, 2022 at 15:35 | answer | added | Christian Remling | timeline score: 6 | |
| May 24, 2022 at 12:13 | answer | added | Denis Serre | timeline score: 7 | |
| May 24, 2022 at 12:07 | history | edited | Denis Serre | CC BY-SA 4.0 |
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| May 24, 2022 at 11:59 | history | edited | Denis Serre | CC BY-SA 4.0 |
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| May 24, 2022 at 11:56 | comment | added | Héhéhé | You should edit your question then because it does not appear. By the way, I guess that you are talking about eigenvalue of the laplacian operator but you didn't write it down. Moreover, it should be $\| \partial_\nu u \|$ rather than $\| \nabla u\|$, shoudn't it? | |
| May 24, 2022 at 11:55 | history | edited | guest61 | CC BY-SA 4.0 |
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| May 24, 2022 at 11:53 | comment | added | guest61 | The eigenfunction is normalized, i.e. $\| u\|_{L^2(P)}=1$ | |
| May 24, 2022 at 11:51 | comment | added | Héhéhé | Since you can multiply an eigenfunction by a non zero constant and still have an eigenfunction, your estimate cannot hold (by making this constant arbitrary large). | |
| May 24, 2022 at 11:25 | history | asked | guest61 | CC BY-SA 4.0 |