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Timeline for Proof of Geisser-Levine

Current License: CC BY-SA 4.0

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May 23, 2022 at 19:40 comment added Marc Hoyois I mean $H^{n-i}(\operatorname{Spec} k, \mathbb Z/p^r(n))=0$ for $i>0$.
May 23, 2022 at 16:55 comment added curious math guy @MarcHoyois Apologies, what do you mean by "there is no motivic cohomology outside of..."?
May 23, 2022 at 16:49 comment added Marc Hoyois I would say that is indeed the argument, however the key point is that in the field case there is no motivic cohomology outside of Milnor K-theory, which is the main result of Geisser-Levine.
May 23, 2022 at 14:13 history asked curious math guy CC BY-SA 4.0