Skip to main content
4 events
when toggle format what by license comment
May 21, 2022 at 6:00 comment added Christian Elsholtz For this example Mathematica gives: $zeta = Exp[2 Pi I/125]; \sum _{i=0}^{24} \text{zeta}^{3\ 6^i+11^i}$ gives $$5 e^{\frac{8 i \pi }{125}}+ 10 e^{-\frac{1}{125} (42 i \pi )}+10 e^{\frac{58 i \pi }{125}}$$, which gives N[\%] 10.9551 +2.23283 i. With $a=1$ it is numerically close to $0$. Can anybody else check this independently?
May 19, 2022 at 2:30 vote accept Asvin
S May 19, 2022 at 2:24 review First answers
May 19, 2022 at 3:29
S May 19, 2022 at 2:24 history answered johng23 CC BY-SA 4.0