Timeline for Is there an open subset $A$ of $[0,1]^2$ with measure $>\frac{1}{100}$ that satisfies this property?
Current License: CC BY-SA 4.0
12 events
when toggle format | what | by | license | comment | |
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S Apr 22, 2023 at 12:56 | history | bounty ended | TheSimpliFire | ||
S Apr 22, 2023 at 12:56 | history | notice removed | TheSimpliFire | ||
Apr 20, 2023 at 20:49 | vote | accept | Saúl RM | ||
Apr 20, 2023 at 15:26 | answer | added | Terry Tao | timeline score: 22 | |
Apr 20, 2023 at 15:10 | comment | added | Yaakov Baruch | Ah, that length requierement slipped beteeen my eyes. Thank you. | |
Apr 20, 2023 at 12:52 | comment | added | Saúl RM | @YaakovBaruch maybe no curve of length $\leq1$ can pass through all the points in that finite set | |
Apr 20, 2023 at 11:40 | comment | added | Yaakov Baruch | $A$ being open and by a compactness argument, couldn't we chose a finite set of points that $\gamma$ needs to go through for $\gamma+A$ to contain a closed ball of radius larger than $\epsilon$? Apologies, I know I'm missing something, but what is it? | |
S Apr 20, 2023 at 8:07 | history | bounty started | TheSimpliFire | ||
S Apr 20, 2023 at 8:07 | history | notice added | TheSimpliFire | Draw attention | |
May 24, 2022 at 12:08 | comment | added | Saúl RM | Cool! I'll try to understand the answer in detail when I have time | |
May 24, 2022 at 4:37 | comment | added | fedja | I answered the original polyomino question (which corresponds to arbitrary rectifiable curves). The smooth curve version is a bit harder and I don't immediately see how to handle it, so it remains open at the moment :-) | |
May 13, 2022 at 23:46 | history | asked | Saúl RM | CC BY-SA 4.0 |