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May 12, 2022 at 19:31 vote accept Adithya Chakravarthy
May 12, 2022 at 16:12 answer added KConrad timeline score: 6
May 12, 2022 at 14:48 comment added Adithya Chakravarthy @KConrad fixed.
May 12, 2022 at 14:48 history edited Adithya Chakravarthy CC BY-SA 4.0
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May 12, 2022 at 14:38 comment added KConrad You still have a typo, writing $(1 + T^a) - 1$, which is just $T^a$, instead of $(1+T)^a-1$. The expression $T^a$ for general $a \in \mathbf Z_p$ is meaningless, but $(1+T)^a - 1 = \sum_{n \geq 1} \binom{a}{n}T^n$ is a legitimate power series in $\mathbf Z_p[[T]]$ for $a \in \mathbf Z_p$.
May 12, 2022 at 14:35 history edited Adithya Chakravarthy CC BY-SA 4.0
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May 12, 2022 at 14:34 comment added Adithya Chakravarthy @efs, yes that was a typo, sorry. And thank you - "composition of power series" was the keyword I needed to make sense of this
May 12, 2022 at 6:07 comment added KConrad You don't say in your question what $\alpha \circ (a)$ means. Perhaps the result you ask about is, up to some normalization, essentially Theorem 1.2 in Chapter 4 of Lang's Cyclotomic Fields I and II.
May 12, 2022 at 5:26 review Close votes
May 21, 2022 at 3:02
May 12, 2022 at 5:06 comment added abx The text you quote does not appear on p. 16, nor on the neighboring pages.
May 12, 2022 at 5:01 comment added efs Anyway, you can always formally take the composition $F(G(T))$ of two power series $F(T)$ and $G(T)=T+\cdots$.
May 12, 2022 at 4:56 comment added efs Are you sure it isn't $(1+T)^a-1$?
May 12, 2022 at 4:43 history edited Adithya Chakravarthy CC BY-SA 4.0
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May 12, 2022 at 4:21 history edited Adithya Chakravarthy CC BY-SA 4.0
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May 12, 2022 at 4:04 history asked Adithya Chakravarthy CC BY-SA 4.0