Timeline for Difference sequences of sets of integers
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 12, 2022 at 7:16 | vote | accept | M.H.Hooshmand | ||
| May 12, 2022 at 4:49 | comment | added | M.H.Hooshmand | @-Thomas Bloom. Thanks again. So we can say $N\leq s$. Any idea for the exact value of $N$? | |
| May 11, 2022 at 9:43 | comment | added | Thomas Bloom | I meant $A_{s+1}=\mathbb{Z}$ above. | |
| May 11, 2022 at 9:20 | comment | added | Thomas Bloom | (b) is still true by Waring's problem - there is some s such that every positive integer is the sum of s kth powers, so certainly A_(k+1) =Z. | |
| May 11, 2022 at 9:11 | answer | added | Glorfindel | timeline score: 2 | |
| May 11, 2022 at 7:45 | history | edited | M.H.Hooshmand | CC BY-SA 4.0 |
added 9 characters in body
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| May 11, 2022 at 7:39 | comment | added | M.H.Hooshmand | Thus, let me to replace it by another question. | |
| May 11, 2022 at 7:29 | comment | added | M.H.Hooshmand | @-Thomas Bloom. Oh yes, right, easy to prove!. Thanks. | |
| May 10, 2022 at 23:38 | comment | added | Thomas Bloom | If I understand the notation correctly, then when $A=\{m^2: m\in \mathbb{Z}\}$ then $A_1$ contains all odd integers so $A_2=\mathbb{Z}=A_3$. | |
| May 10, 2022 at 19:15 | history | asked | M.H.Hooshmand | CC BY-SA 4.0 |