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Sep 8, 2022 at 11:34 vote accept fatpanda2049
Jun 7, 2022 at 11:45 answer added Ilya Bogdanov timeline score: 2
May 11, 2022 at 10:49 history undeleted fatpanda2049
May 11, 2022 at 8:58 history deleted fatpanda2049 via Vote
May 11, 2022 at 8:41 comment added fatpanda2049 That question $a,b\in \{0,1\}^p$ and one can utilize set algebra. Here the setting is quite different.
May 11, 2022 at 8:33 comment added Carlo Beenakker see also: mathoverflow.net/q/18084/11260 --- Is the Jaccard distance a distance?
S May 11, 2022 at 1:43 history suggested CommunityBot CC BY-SA 4.0
MathJax corrections
May 10, 2022 at 20:19 review Suggested edits
S May 11, 2022 at 1:43
May 10, 2022 at 17:20 comment added fatpanda2049 $a \odot b$ is the element-wise product, not inner product. So $a\odot b$ and $a-b$ are both of length $p$, right?
May 10, 2022 at 14:37 comment added kodlu you do realise that $a-b$ is of different length than $a\odot b.$ Whats the motivation for this definition?
May 10, 2022 at 13:57 history edited fatpanda2049 CC BY-SA 4.0
added 355 characters in body
May 10, 2022 at 12:56 comment added fatpanda2049 Thanks for pointing it out. Please see the edited version. It is the Hadamard product between $a$ and $b$.
May 10, 2022 at 12:55 history edited fatpanda2049 CC BY-SA 4.0
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May 10, 2022 at 12:50 comment added Michael Albanese What do you mean by $ab$?
S May 10, 2022 at 12:47 review First questions
May 10, 2022 at 12:50
S May 10, 2022 at 12:47 history asked fatpanda2049 CC BY-SA 4.0