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Oct 16, 2010 at 12:56 vote accept Bruno Galvan
Oct 14, 2010 at 23:58 answer added Anton Petrunin timeline score: 6
Oct 14, 2010 at 23:08 comment added Suresh Venkat There's an interesting discussion at this question: mathoverflow.net/questions/32527/… on different ways to quantify the complexity of a (Riemannian) metric. That might provide some candidates for your preferred embedding.
Oct 14, 2010 at 21:08 comment added Bruno Galvan I have in mind that the preferred embedding has something to do with the curvature of the manifold, e.g., in the preferred embedding the manifold has the minimal curvature. This is for example the case of the set with three elements. For the moment I do not consider the masses of the particles.
Oct 14, 2010 at 20:14 answer added Suresh Venkat timeline score: 2
Oct 14, 2010 at 19:37 comment added Richard Montgomery Do you have any thoughts, or suggested axiomatics on what ``preferred'' might mean? Do you want your points to have masses? Gromov has, somewhere, (perhaps in `Metric Structures') some results about embeddings of 4 point spaces that may be of use.
Oct 14, 2010 at 19:29 comment added j.c. A question about isometrically embedding finite metric spaces into Euclidean spaces is here: mathoverflow.net/questions/12394/… I don't know if any of the results extend to isometric embeddings into Riemannian manifolds.
Oct 14, 2010 at 18:28 history edited Bruno Galvan CC BY-SA 2.5
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Oct 14, 2010 at 18:19 history asked Bruno Galvan CC BY-SA 2.5