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May 4, 2022 at 10:03 history edited Peter Taylor CC BY-SA 4.0
added 390 characters in body
May 4, 2022 at 9:06 comment added AgnostMystic Exactly,that is what I have a bit of difficulty in understanding
May 4, 2022 at 8:59 comment added Peter Taylor @AgnostMystic, the jump to the final line is without argument. If you want to fill in the details there, you can easily check it for small $n$ and then prove it by induction on $n$, where the proof of the inductive step uses another induction, this time on $k$. Was that the part which you wanted me to amplify?
May 4, 2022 at 7:34 comment added AgnostMystic Peter Taylor,thank you for your answer .Could you kindly explain a bit in more detail?I could not completely understand it
May 2, 2022 at 19:16 history answered Peter Taylor CC BY-SA 4.0