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Jun 23, 2022 at 15:49 comment added Salvatore Siciliano Actually, the result holds for arbitrary Lie algebras over fields of characteristic zero. This was noticed by Bahturin in his book "Identities on Lie algebras".
May 1, 2022 at 6:49 vote accept Functor
May 1, 2022 at 5:57 history edited Grisha Papayanov CC BY-SA 4.0
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May 1, 2022 at 5:56 comment added Grisha Papayanov @YCor That is true; the article only claims the result for finite-dimensional Lie algebras.
May 1, 2022 at 5:44 comment added YCor But this fact (existence of a non-abelian 2-dimensional or 3-dimensional nonabelian subalgebra) is true for finite-dimensional non-abelian Lie algebras, but not in general. For instance, it fails for free Lie algebras.
May 1, 2022 at 5:17 history answered Grisha Papayanov CC BY-SA 4.0