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May 2, 2022 at 18:01 comment added Mikhail Borovoi I think YES, at least when ${\rm char}(k)=0$. Indeed, let $n\in N_G(S)(k)$ be a representative of $w\in{}_k W$. Then ${\rm Ad}(n){\mathfrak g}_\alpha={\mathfrak g}_{w.\alpha}$ and similarly for ${\mathfrak g}_{2\alpha}$ if $2\alpha$ is a root. The desired assertion follows.
S May 1, 2022 at 0:35 review First questions
May 1, 2022 at 1:26
S May 1, 2022 at 0:35 history asked Lisa CC BY-SA 4.0