Timeline for Coefficients of certain Taylor series
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 2, 2022 at 15:21 | vote | accept | Iosif Pinelis | ||
| Apr 29, 2022 at 19:42 | comment | added | Iosif Pinelis | @IraGessel : Thank you for your comment. | |
| Apr 29, 2022 at 19:40 | comment | added | Ira Gessel | The coefficients of $2g(t)$, as an exponential generating function, are sequence A211393 of the OEIS (oeis.org/A211393) and this formula for $\ln(2g(t))$ can be found there. | |
| Apr 29, 2022 at 19:38 | comment | added | Iosif Pinelis | @ChristopheLeuridan : Thank you for your comment. That $2t$ was multiplied by $\frac12$, which you may not have noticed. I have now rewritten the expression in an equivalent, but slightly simpler, form. | |
| Apr 29, 2022 at 19:36 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
deleted 12 characters in body
|
| Apr 29, 2022 at 19:32 | comment | added | Christophe Leuridan | @losif Pinelis By computing the sum of the two fractions defining $f(t)$, I find the same answer, excepted that I have $t \tanh^{-1}(t)$ instead of $2t \tanh^{-1}(t)$. But I get the same final formula. | |
| Apr 29, 2022 at 19:27 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
deleted 6 characters in body
|
| Apr 29, 2022 at 19:16 | history | answered | Iosif Pinelis | CC BY-SA 4.0 |