Timeline for Coefficients of certain Taylor series
Current License: CC BY-SA 4.0
13 events
| when toggle format | what | by | license | comment | |
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| Aug 2, 2022 at 15:21 | vote | accept | Iosif Pinelis | ||
| Apr 29, 2022 at 19:29 | comment | added | Iosif Pinelis | @T.Amdeberhan : Thank you for your further comment. Taking the log indeed helps. | |
| Apr 29, 2022 at 19:16 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
deleted 137 characters in body
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| Apr 29, 2022 at 19:16 | answer | added | Iosif Pinelis | timeline score: 2 | |
| Apr 29, 2022 at 19:15 | history | undeleted | Iosif Pinelis | ||
| Apr 29, 2022 at 19:09 | history | deleted | Iosif Pinelis | via Vote | |
| Apr 29, 2022 at 19:08 | history | undeleted | Iosif Pinelis | ||
| Apr 29, 2022 at 18:59 | history | deleted | Iosif Pinelis | via Vote | |
| Apr 29, 2022 at 18:59 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
added 137 characters in body
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| Apr 29, 2022 at 18:42 | comment | added | T. Amdeberhan | Also, what you put in the questions, such as #1, and restricting to $f_1(t)$, a similar manifestation works for the series of $F_1(t)=\frac{1-t}2\log\left(\frac{1+t}{1-t}\right)$. Inherited by $f_1(t)$. But, it is easier to see in $F_1(t)$ than $f_1(t)$. | |
| Apr 29, 2022 at 18:37 | comment | added | Iosif Pinelis | @T.Amdeberhan : Yes, of course. Thank you for your comment. It may be interesting that apparently $f_1^{(2k)}(0)/(2k)!=f_1^{(2k+1)}(0)/(2k+1)!$ for all $k=0,1,\dots$. | |
| Apr 29, 2022 at 18:28 | comment | added | T. Amdeberhan | In analyzing $f(t)$, it might suffice to study one part of $f$. That is, $f_1(t)=\left(\frac{1+t}{1-t}\right)^{(1-t)/2}$. I'm sure you knew that. | |
| Apr 29, 2022 at 16:18 | history | asked | Iosif Pinelis | CC BY-SA 4.0 |