Timeline for Making MATLAB svd robust to transpose operation
Current License: CC BY-SA 2.5
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Oct 14, 2010 at 13:18 | comment | added | İsmail Arı | Actually, the scalar products always be +/-1. I couldn't understand clearly how to do a normalization on comparison operator. The trick is to not to compute all svd but solve it partially. I tried and added another piece of code into the question where I used svd() function with economic usage, where it finds only min(M,N) singular vectors. The significant vectors again do not fit in sign. | |
Oct 14, 2010 at 11:05 | history | answered | Federico Poloni | CC BY-SA 2.5 |