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Apr 27, 2022 at 3:35 comment added GH from MO @ZachTeitler: $2^{2^{n-1}}+1$ is sharp, and this was proved in 1973 independently by Burkill-Mirsky and Kalmanson. Check out the abstract of doi.org/10.37236/9880
Apr 26, 2022 at 23:41 comment added Zach Teitler Recursively any $2^{2^{n-1}}+1$ points in $\mathbb{R}^n$ have some 3 points with monotonic coordinates. I wonder if it is sharp, are there some $2^{2^{n-1}}$ points no 3 of which have monotonic coordinates? It seems like a lot of points.
Apr 26, 2022 at 1:09 vote accept aradarbel10
Apr 26, 2022 at 1:04 history edited GH from MO CC BY-SA 4.0
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Apr 26, 2022 at 0:57 history answered GH from MO CC BY-SA 4.0