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Oct 14, 2010 at 12:13 vote accept Victor
Oct 14, 2010 at 7:15 answer added Bruno Martelli timeline score: 6
Oct 14, 2010 at 6:32 comment added Victor Do you expect the set of connected components to be uncountable for the space of embeddings of the Whitehead manifold in R^3?
Oct 14, 2010 at 4:05 comment added Ryan Budney With contractible manifolds it's the "ends" of the manifolds that are interesting so configuration spaces in the manifold shouldn't see anything interesting unless you choose some funny notion of configuration space -- I imagine configuration spaces aren't "cofinal enough" to see ends. Off the top of my head I'm not sure what topology I'd want to put on a space of embeddings of a contractible manifold into a euclidean space. But with whatever definition there should be many embeddings -- when constructing the Whitehead manifold you can use various "twist" variations of the Whitehead link.
Oct 14, 2010 at 3:35 history asked Victor CC BY-SA 2.5