Timeline for On the fundamental dimension of a polyhedron
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 25, 2022 at 3:49 | comment | added | M.Ramana | @MarkGrant Thanks a lot for your comment and the link. | |
| Apr 25, 2022 at 3:49 | comment | added | M.Ramana | @JohnRognes Thank you so much for the example. Is any condition on $P$ under which we have $Fd(A)<Fd(P)$? | |
| Apr 24, 2022 at 19:38 | comment | added | John Rognes | No. $A = S^1$ is a retract of $P = S^1 \vee S^1$, this $P$ is not a retract up to homotopy of this $A$, and the `fundamental dimension' is $1$ for both $A$ and $P$. | |
| Apr 24, 2022 at 17:09 | comment | added | Mark Grant | If there exists a finitely dominated space A whose finiteness obstruction is nontrivial, that would give a counter example. | |
| Apr 24, 2022 at 17:07 | comment | added | Mark Grant | en.m.wikipedia.org/wiki/Wall%27s_finiteness_obstruction | |
| Apr 24, 2022 at 14:45 | history | asked | M.Ramana | CC BY-SA 4.0 |