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Apr 22, 2022 at 22:55 comment added Will Sawin @LSpice Yes, but existence is a consequence of the existence of $P$, not of the existence of $f$.
Apr 22, 2022 at 22:05 comment added LSpice Sure, uniqueness is surely implicit, but isn't the quoted passage also claiming existence?
Apr 22, 2022 at 22:00 comment added Will Sawin @LSpice To me the phrase "induces a morphism" implies uniqueness. But my goal was also to answer the question about "I meet in some papers in complex algebraic geometry that people define a morphism by claiming on closed points." You can't define a morphism in this way unless you specify a unique morphism.
Apr 22, 2022 at 21:49 comment added LSpice But the quoted passage is really saying that a bijection comes from a morphism, not just that, if it comes from a morphism, then it comes from a unique such … isn't it?
Apr 22, 2022 at 21:09 history answered Will Sawin CC BY-SA 4.0