Timeline for Inverse Mellin transform of 3 gamma functions product
Current License: CC BY-SA 4.0
15 events
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| Apr 22, 2022 at 12:04 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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| Apr 22, 2022 at 11:30 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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| Apr 22, 2022 at 11:26 | comment | added | Carlo Beenakker | @Pouya --- OK, I also calculated the result "manually", as requested; all poles contribute to the contour integral. | |
| Apr 22, 2022 at 11:25 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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| Apr 21, 2022 at 21:39 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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| Apr 21, 2022 at 21:16 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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| Apr 21, 2022 at 20:27 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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| Apr 21, 2022 at 20:17 | history | rollback | Carlo Beenakker |
Rollback to Revision 2
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| Apr 21, 2022 at 20:14 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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| Apr 21, 2022 at 19:57 | comment | added | Pouya | I want to know which poles is used? Any 3 poles? | |
| Apr 21, 2022 at 19:51 | comment | added | Pouya | I do not want to use Mathematica or any computing software. I want it to be calculated manually. | |
| Apr 21, 2022 at 19:46 | comment | added | Carlo Beenakker | I applied the Mellin inversion formula to the line $\text{Re}\,s=\gamma$ that avoids the three poles you noted in your post; the integral is then evaluated by Mathematica | |
| Apr 21, 2022 at 19:43 | comment | added | Pouya | I don't understand your answer. Can you explain for me what did you do? | |
| Apr 21, 2022 at 19:26 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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| Apr 21, 2022 at 19:09 | history | answered | Carlo Beenakker | CC BY-SA 4.0 |