Timeline for The monodromy in the proof of Little Picard via Klein's $J$
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
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| Apr 21, 2022 at 18:02 | history | edited | Alexandre Eremenko | CC BY-SA 4.0 |
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| Apr 21, 2022 at 14:20 | comment | added | Alexandre Eremenko | @Manuel Eberl: I only wanted to say that $\lambda$ is a simpler function than $J$ since $\lambda$ is a universal covering, and $J$ is a ramified covering. | |
| Apr 21, 2022 at 14:17 | comment | added | Alexandre Eremenko | @Manuel Eberl: Look at the "Zalcman's Elementary proof" in my reference. If $f$ omits $0,1,\infty$, then $f=\exp(g)$ where $g$ omits the sequence $2\pi in$. This is the beginning of Zalcman's proof. | |
| Apr 21, 2022 at 8:54 | comment | added | Manuel Eberl | Also thanks for bringing $\lambda$ to my attention, but does all of this mean that if you want to do the proof with $J$ then you need to prove that $J$ is a covering map first? And if so, is the only way to do it the hard way, i.e. by showing explicitly that for each value in the range a corresponding disjoint union of neighbourhoods in the preimage exists? | |
| Apr 21, 2022 at 8:53 | comment | added | Manuel Eberl | I don't understand the last comment about $\exp$ at all. Surely $\exp$ does not omit 1? | |
| Apr 21, 2022 at 2:17 | history | answered | Alexandre Eremenko | CC BY-SA 4.0 |