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Apr 25, 2022 at 8:03 vote accept Danilo Gregorin Afonso
Apr 21, 2022 at 12:47 comment added Denis Serre Yes, bootstrapping works, as long as $f$ has some regularity/
Apr 21, 2022 at 9:55 comment added Danilo Gregorin Afonso Dear Prof Serre, thank you for your answer. However, so far we know only that $u_j \in H_0^1 \cap L^\infty$. Can we assume smoothness already by bootstrapping arguments? (I'm sorry, I still struggle with these elliptic regularity arguments)
Apr 20, 2022 at 16:12 history answered Denis Serre CC BY-SA 4.0