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Apr 20, 2022 at 8:36 comment added Aurel @BenMares The way I understood the question, the OP wanted an order of magnitude. But I agree that the question of the exact bound is not solved for all $n$.
Apr 20, 2022 at 8:00 comment added Ben Mares What about an upper bound? If $n$ is not divisible by 8, then $D_n$ is above the lower bound by a factor of $2$. When $n$ is 1 mod 8, then $kE_8\oplus A_2$ is above by a factor of $\sqrt{3}$. Can this be improved?
Apr 20, 2022 at 0:22 comment added Yoav Kallus And this bound is achieved whenever n is divisible by 8. See: en.wikipedia.org/wiki/Unimodular_lattice
Apr 19, 2022 at 21:54 vote accept Eric Naslund
Apr 19, 2022 at 21:53 history answered Aurel CC BY-SA 4.0